The quality 12v 5 pin relay belongs to a classification of relay products, and it also has certain requirements for the operating environment. So the popular knowledge today is about the working principle of quality 12v 5 pin relay and the content of reference value in power calculation. Friends who are interested can learn from the actual situation.

How much power is the quality 12v 5 pin relay coil

The coil current of the quality 12v 5 pin relay is approximately between 30 and 70 mA, with a typical value of 45 mA. Therefore, the typical value of the coil power is: 12V × 45mA = 0.54W. The maximum value is approximately: 12v × 70mA = 0.84W

The working principle of quality 12v 5 pin relay is generally composed of iron core, coil, armature, contact reed, etc. As long as a certain voltage is applied to both ends of the coil, a certain current will flow in the coil, which will produce electromagnetic effects. Under the action of electromagnetic force, the armature will overcome the pulling force of the return spring and attract to the core, thereby driving the armature. The moving contact and the static contact (normally open contact) are pulled together. When the coil is de-energized, the electromagnetic attraction will disappear, and the armature will return to its original position under the reaction force of the spring, releasing the moving contact and the original static contact (normally closed contact). This pulls in and releases, so as to achieve the purpose of conducting and cutting off in the circuit. The "normally open and normally closed" contacts of the relay can be distinguished as follows: the static contact that is in the off state when the relay coil is not energized is called "normally open contact"; the static contact that is in the on state is called It is a "normally closed contact".